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How do I force a particular instance of a C++ template to …
https://stackoverflow.com/questions/2152002/how-do-i-force-a-particular-instance-of-a-c-template-to-instantiate
Show activity on this post. You can't force generic templates to instantiate, the compiler can only generate code if the type is completely known. Forcing an instantiation is done by providing all types explicitly: template class std::vector<int>; Comeaus template FAQ covers the related issues in some detail. Share. Reviews: 1
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Function Template Instantiation | Microsoft Docs
https://docs.microsoft.com/en-us/cpp/cpp/function-template-instantiation
Aug 03, 2021 · When a function template is first called for each type, the compiler creates an instantiation. Each instantiation is a version of the templated function specialized for the type. This instantiation will be called every time the function is used for the type.
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Template instantiation (C++ only)
https://www.ibm.com/docs/en/i/7.3?topic=only-template-instantiation-c
Template instantiation (C++ only) The act of creating a new definition of a function, class, or member of a class from a template declaration and one or more template arguments is called template instantiation. The definition created from a template instantiation to handle a specific set of template arguments is called a specialization.
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c++ - Force explicit template instantiation with CRTP - Stack …
https://stackoverflow.com/questions/24725152/force-explicit-template-instantiation-with-crtp
Sep 25, 2014 · [temp.inst]/2 about implicit instantiation: "Unless a member of a class template or a member template has been explicitly instantiated or explicitly specialized, the specialization of the member is implicitly instantiated when the specialization is referenced in a context that requires the member definition to exist; in particular, the initialization (and any associated side …
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c++ - How do I explicitly instantiate a template function
https://stackoverflow.com/questions/4933056/how-do-i-explicitly-instantiate-a-template-function
If you really want to instantiate (instead of specialize or something) the function, do this: template <typename T> void func (T param) {} // definition template void func<int> (int param); // explicit instantiation. There seems to be (a lot) of confusion regarding explicit …
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8.14 — Function template instantiation – Learn C++
https://www.learncpp.com/cpp-tutorial/function-template-instantiation/
Mar 29, 2022 · An instantiated function is often called a function instance ( instance for short) or a template function. Function instances are normal functions in all regards. The process for instantiating a function is simple: the compiler essentially clones the function template and replaces the template type ( T) with the actual type we’ve specified ( int ).
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Explicit Instantiation | Microsoft Docs
https://docs.microsoft.com/en-us/cpp/cpp/explicit-instantiation
Aug 03, 2021 · You can use the extern keyword to keep the compiler from generating the same instantiation code in more than one object module. You must instantiate the template function by using the specified explicit template parameters in at least one linked module if the function is called, or you will get a linker error when the program is built. Note
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Explicit Template Instantiation - C++ Articles
https://cplusplus.com/articles/1C75fSEw/
Jun 25, 2011 · The above example indeed does compile but it does not contain the given template instance. However, we can add specialized template support through explicit template instantiation which will add the symbols needed to link (properly) against the library for use. Take the following revision of the Example.cpp: 1. 2.
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c++ force template instantiation
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